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Question: The acceleration due to gravity and density of the earth are related by which of the following relat...

The acceleration due to gravity and density of the earth are related by which of the following relations ? (where G is the gravitational constant and RER_{E} is the radius of the earth)

A

ρ=4πGRE3g\rho = \frac{4\pi GR_{E}}{3g}

B

ρ=3g4πGRE\rho = \frac{3g}{4\pi GR_{E}}

C

ρ=3G4πgRE\rho = \frac{3G}{4\pi gR_{E}}

D

ρ=4πgRE3G\rho = \frac{4\pi gR_{E}}{3G}

Answer

ρ=3g4πGRE\rho = \frac{3g}{4\pi GR_{E}}

Explanation

Solution

Accelerations due to gravity on earth is

g=GMERE2g = \frac{GM_{E}}{R_{E}^{2}} ….. (i)

As ρ=ME43πRE3ME=ρ43πRE3\rho = \frac{M_{E}}{\frac{4}{3}\pi R_{E}^{3}} \Rightarrow M_{E} = \rho\frac{4}{3}\pi R_{E}^{3}

Substituting this value in Eq. (i), we get

g=G(ρ43πRE3)RE2=43πρGREorρ=3g4πGREg = \frac{G\left( \rho\frac{4}{3}\pi R_{E}^{3} \right)}{R_{E}^{2}} = \frac{4}{3}\pi\rho GR_{E}or\rho = \frac{3g}{4\pi GR_{E}}