Question

The absorption transition between two energy states of hydrogen atom are 3. The emission transitions between these states will be

• A. 3
• B. 4
• C. 5
• D. 6

Answer 1

Answer: (D)

6

Answer 2

Number of absorption lines = (n – 1) ⇒ 3 = (n – 1) ⇒ n = 4

Hence number of emitted lines $= \frac{n(n - 1)}{2} = \frac{4(4 - 1)}{2} = 6$