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Question: The absolute temperatures of two black bodies are 2000 K and 3000 K respectively. The ratio of wavel...

The absolute temperatures of two black bodies are 2000 K and 3000 K respectively. The ratio of wavelengths corresponding to maximum emission of radiation by them will be

A

2 : 3

B

3 : 2

C

9 : 4

D

4 : 9

Answer

3 : 2

Explanation

Solution

λmT=λm′T′\lambda _ { m } T = \lambda _ { m } ^ { \prime } T ^ { \prime } ⇒ λmλm′=T′T=30002000=32\frac { \lambda _ { m } } { \lambda _ { m } ^ { \prime } } = \frac { T ^ { \prime } } { T } = \frac { 3000 } { 2000 } = \frac { 3 } { 2 }