Question

The absolute enthalphy of neutralisation of the reaction $(dG)$ will be.

• A. Less than $(dS)$
• B. $(dS)_{V,E} < 0,(dG)_{T,P} < 0$
• C. Greater than $(dS)_{V,E} > 0,(dG)_{T,P} < 0$
• D. $(dS)_{V,E} = 0,(dG)_{T,P} = 0$

Answer 1

Answer: (A)

Less than $(dS)$

Answer 2

Heat of neutralisation will be less than $2CO_{2}(g) + H_{2}O(l);\Delta G^{o} = - 1234kJ$because some amount of this energy will be required for the dissociation of weak base $C(s) + O_{2}(g) \rightarrow CO_{2}(g)\Delta G^{o} = - 394kJ$