Question
Question: The A.M. of a set of 50 numbers is 38. If two numbers of the set, namely 55 and 45 are discarded, th...
The A.M. of a set of 50 numbers is 38. If two numbers of the set, namely 55 and 45 are discarded, the A.M. of the remaining set of numbers is:
A) 36
B) 36.5
C) 37.5
D) 38.5
Solution
Here we will find the A.M (Arithmetic Mean) of the remaining numbers by using the data given to us. We will find the sum of all the numbers by using the A.M formula and then subtract the two numbers which are discarded from it. Then we will divide the new sum by the remaining numbers to get the new A.M.
Formula used:
A.M=n1i=1∑nai, where, A.M is Arithmetic Mean, n is number of values and ai is the data set of values
Complete step by step solution:
We know that A.M of 50 given numbers is 38.
Let the sum of 50 numbers be x.
Therefore, using the formula of arithmetic mean, we get
A.M =50x
\Rightarrow 38 = \dfrac{x}{{50}}$$$$$$
On cross multiplication, we get \Rightarrow x = 38 \times 50 \Rightarrow x = 1900So,sumof50numbersis1900.Now,itisgiventhattwonumbers55,45arediscardedsothesumofnumberafterremovingthemis:Newsum = 1900 - \left( {55 + 45} \right)Addingthetermsinsidethebracket,weget \Rightarrow Newsum = 1900 - 100Subtractingtheterms,weget \Rightarrow Newsum = 1800So,ournewsumof48numbersis1800.Therefore,A.Moftheremaining48numbersisgivenbydividingnewsumbyremainingnumbers.Nowusingtheformulaofarithmeticnumber,wegetA.M = \dfrac{{1800}}{{48}}Dividingtheterms,weget \Rightarrow A.M = 37.5So,A.Moftheremainingnumberis37.5$$.
Hence, option (C) is correct.
Note:
Arithmetic Mean is also known as the average of a set of numbers. We can use a direct method by subtracting 55 and 45 by the product of the original A.M and the original set of numbers and then divide it by 48 as two numbers are being removed.
So, we get our equation as:
A.M = \dfrac{{\left[ {50 \times 38} \right] - 55 - 45}}{{50 - 2}}$$$$$$
Simplifying the expression, we get \Rightarrow A.M = \dfrac{{1800}}{{48}}Dividingtheterms,weget \Rightarrow A.M = 37.5So,A.Moftheremainingnumberis37.5$$.