Solveeit Logo

Question

Question: The 6<sup>th</sup> term of an A.P. = 2, the value of common different of an A.P. which makes the pro...

The 6th term of an A.P. = 2, the value of common different of an A.P. which makes the product a1.a4.a6 least is –

A

d = 8/5

B

d = 5/4

C

d = 2/3

D

None of these

Answer

None of these

Explanation

Solution

y = a1.a2.a6 a + 5d = 2

y = 2a.(a + 3d) a = 2 – 5d

y = 2(2 – 5d) (2 – 5d + 3d)

y = 2(5d – 2) (2d – 2) d1= 25\frac { 2 } { 5 } d2=1

Y(min) at d = d1+d22\frac { \mathrm { d } _ { 1 } + \mathrm { d } _ { 2 } } { 2 } = 25+12\frac { \frac { 2 } { 5 } + 1 } { 2 } = 710\frac { 7 } { 10 }