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Question: The \( 1gram \) of a carbonate \( \left( {{M_2}C{O_3}} \right) \) on treatment with excess \( HCl \)...

The 1gram1gram of a carbonate (M2CO3)\left( {{M_2}C{O_3}} \right) on treatment with excess HClHCl produces 0.011860.01186 mole of CO2C{O_2} the molar mass of M2CO3{M_2}C{O_3} in gmole1g mol{e^{ - 1}} is:
A.A. 11861186
B.B. 84.384.3
C.C. 118.6118.6
D.D. 11.8611.86

Explanation

Solution

The molar mass of carbonate (M2CO3)\left( {{M_2}C{O_3}} \right) can be calculated by finding a relation between numbers of mole, mass and molar mass. We know the number of moles of substance is equal to the given mass of substance divided by its molar mass.
Formula used
n=mMn = \dfrac{m}{M}
Where, nn is the number of moles of substance, mm is the given mass of substance and MM is the molar mass of substance.

Complete step by step solution
In the question it is given that 1gram1gram of a carbonate (M2CO3)\left( {{M_2}C{O_3}} \right) on treatment with excess HClHCl produces 0.011860.01186 mole of CO2C{O_2} , we have to calculate the molar mass of carbonate (M2CO3)\left( {{M_2}C{O_3}} \right) .
This is the reaction, according to the given question,
M2CO3+2HCl2MCl+H2O+CO2{M_2}C{O_3} + 2HCl \to 2MCl + {H_2}O + C{O_2}
Now, from the reaction we may conclude that moles of CO2C{O_2} is equal to moles of M2CO3{M_2}C{O_3} that is equal to 1gram1gram of M2CO3{M_2}C{O_3} .
i.e. 0.011860.01186 moles of CO2C{O_2} =0.01186= 0.01186 moles of M2CO3{M_2}C{O_3} == 1g1g M2CO3{M_2}C{O_3}
Hence, we know the relation between numbers of moles, mass and molar mass.
n=mMn = \dfrac{m}{M}
By putting the value of the number of moles of M2CO3{M_2}C{O_3} and its mass, we can calculate the molar mass of M2CO3{M_2}C{O_3} in the above equation.
0.01186=1M0.01186 = \dfrac{1}{M}
\Rightarrow M=10.01186M = \dfrac{1}{{0.01186}}
M=84.3gmole1M = 84.3gmol{e^{ - 1}}
Therefore, the molar mass of carbonate is found to be 84.3gmole184.3gmol{e^{ - 1}} . Thus, the correct option is A.A.

Additional information
Molar mass: it is the total mass of all the atoms in a molecule, it is denoted by atomic mass unit (amu)\left( {amu} \right) . Its unit is g/moleg/mole

Note
It is to be noted that mole represent 6.022×10236.022 \times {10^{23}} atoms, molecules or ions of a substance or the amount of substance is equal to its gram atomic mass or molecular mass and a definite number of atoms, molecules or ions of a substance.