Question

$\text{Pt }|\ (H_{2})\ |\text{ pH = 1 }||\text{ pH = 2 }|\ (H_{2})\text{Pt}$atm 1 atm

The cell reaction for the given cell is :

• A. Spontaneou
• B. Non – spontaneous
• C. Equilibrium
• D. None of these

Answer 1

Answer: (B)

Non – spontaneous

Answer 2

}{2H_{\left( 10^{- 3}M \right)}^{+} + 2e\overset{\quad\quad}{\rightarrow} - H_{2} }$$$2H_{\left( 10^{- 3}M \right)}^{+}\overset{\quad\quad}{\rightarrow}2H_{\left( 10^{- 2}M \right)}^{+}E = 0 - \frac{0.0591}{2}{\log\left( \frac{10^{- 1}}{10^{- 2}} \right)}^{2}$E $\rightarrow$ – ve (Non spontaneaous)