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Question

Question: \[\text{cosec}x\cot x + c\]...

cosecxcotx+c\text{cosec}x\cot x + c

A

{1+2tanx(tanx+secx)}1/2dx=\int_{}^{}{\{ 1 + 2\tan x(\tan x + \sec x)\}^{1/2}dx =}

B

log(secx+tanx)+c\log(\sec x + \tan x) + c

C

log(secx+tanx)1/2+c\log(\sec x + \tan x)^{1/2} + c

D

None of these

Answer

log(secx+tanx)+c\log(\sec x + \tan x) + c

Explanation

Solution

logtanθ+12tan2θ+c{logtan}\theta + \frac{1}{2}\tan^{2}\theta + c

1cos1x.1x2dx=\int_{}^{}{\frac{1}{\cos^{- 1}x.\sqrt{1 - x^{2}}}dx =}.