Solveeit Logo

Question

Question: CH$_2$(CO$_2$Me)$_2$ + $\xrightarrow[\text{NaOEt}]{\text{excess}}$ (P) $\xrightarrow[2. \text{ HCl, ...

CH2_2(CO2_2Me)2_2 + NaOEtexcess\xrightarrow[\text{NaOEt}]{\text{excess}} (P) 2. HCl, Δ1. aq NaOH\xrightarrow[2. \text{ HCl, }\Delta]{1. \text{ aq NaOH}} (Q)

If number of sp3sp^3 hybridised C-atoms in (Q) is x and degree of unsaturation of compound (Q) is y, then find the value of [1+xy][1 + \frac{x}{y}]

Answer

3

Explanation

Solution

The reaction sequence leads to cyclobutanecarboxylic acid (Q). The cyclobutane ring contains 4 sp3sp^3 hybridized carbon atoms, so x=4x=4. The molecule has one ring and one carbonyl group, giving a degree of unsaturation y=2y=2. Therefore, [1+xy]=[1+42]=3[1 + \frac{x}{y}] = [1 + \frac{4}{2}] = 3.