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Question

Chemistry Question on Organic Chemistry

Match List I with List II\textbf{Match List I with List II}
\begin{array}{|c|c|c|} \hline \text{List I (Compound)} & \text{List II (p}K_a\text{ value)} \\\ \hline \text{A. Ethanol} & \text{I. } 10.0 \\\ \text{B. Phenol} & \text{II. } 15.9 \\\ \text{C. m-Nitrophenol} & \text{III. } 7.1 \\\ \text{D. p-Nitrophenol} & \text{IV. } 8.3 \\\ \hline \end{array}
Choose the correct answer from the options given below :-\text{Choose the correct answer from the options given below :-}

A

A-I, B-II, C-III, D-IV

B

A-IV, B-I, C-II, D-III

C

A-III, B-IV, C-I, D-II

D

A-II, B-I, C-IV, D-III

Answer

A-II, B-I, C-IV, D-III

Explanation

Solution

The correct matching is as follows:

- A. Ethanol has a pKpK value of 15.9, so AIIA - II.
- B. Phenol has a pKpK value of 10.0, so BIB - I.
- C. mm-Nitrophenol has a pKpK value of 8.3, so CIVC - IV.
- D. pp-Nitrophenol has a pKpK value of 7.1, so DIIID - III.

Hence, the correct matching is AII,BI,CIV,DIIIA - II, B - I, C - IV, D - III.

The Correct Answer is: A-II, B-I, C-IV, D-III