Question
Chemistry Question on Organic Chemistry
Match List I with List II
\begin{array}{|c|c|c|} \hline \text{List I (Compound)} & \text{List II (p}K_a\text{ value)} \\\ \hline \text{A. Ethanol} & \text{I. } 10.0 \\\ \text{B. Phenol} & \text{II. } 15.9 \\\ \text{C. m-Nitrophenol} & \text{III. } 7.1 \\\ \text{D. p-Nitrophenol} & \text{IV. } 8.3 \\\ \hline \end{array}
Choose the correct answer from the options given below :-
A-I, B-II, C-III, D-IV
A-IV, B-I, C-II, D-III
A-III, B-IV, C-I, D-II
A-II, B-I, C-IV, D-III
A-II, B-I, C-IV, D-III
Solution
The correct matching is as follows:
- A. Ethanol has a pK value of 15.9, so A−II.
- B. Phenol has a pK value of 10.0, so B−I.
- C. m-Nitrophenol has a pK value of 8.3, so C−IV.
- D. p-Nitrophenol has a pK value of 7.1, so D−III.
Hence, the correct matching is A−II,B−I,C−IV,D−III.
The Correct Answer is: A-II, B-I, C-IV, D-III