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Chemistry Question on Chemical Reactions of Haloalkanes and Haloarenes

A and B formed in the following reactions are:\textbf{A and B formed in the following reactions are:} CrO2Cl2+4NaOHA+2NaCl+2H2O\text{CrO}_2\text{Cl}_2 + 4\text{NaOH} \rightarrow \text{A} + 2\text{NaCl} + 2\text{H}_2\text{O} A+2HCl+2H2O2B+3H2O\text{A} + 2\text{HCl} + 2\text{H}_2\text{O}_2 \rightarrow \text{B} + 3\text{H}_2\text{O}

A

\text{A} = \text{Na}_2\text{CrO}_4, \, \text{B} = \text{CrO}_3 \\\

B

\text{A} = \text{Na}_2\text{Cr}_2\text{O}_4, \, \text{B} = \text{CrO}_4 \\\

C

\text{A} = \text{Na}_2\text{Cr}_2\text{O}_7, \, \text{B} = \text{CrO}_3 \\\

D

\text{A} = \text{Na}_2\text{Cr}_2\text{O}_7, \, \text{B} = \text{CrO}_5 \\\

Answer

\text{A} = \text{Na}_2\text{CrO}_4, \, \text{B} = \text{CrO}_3 \\\

Explanation

Solution

To analyze the reactions, we need to identify the products formed in each step.

First Reaction: The reaction of dichromate with sodium hydroxide produces sodium chromate:

Cr2O72− + 4NaOH -> 2Na2CrO4 + 2H2O

The product formed in this reaction is Na2CrO4.

Second Reaction: The sodium chromate reacts with chlorine gas and water. The products typically involve the formation of chromium trioxide:

A + 2Cl2 + 2H2O -> B + 3H2O

Here, B is identified as CrO3 (chromium trioxide) when considering oxidation reactions of chromium compounds.

Thus, the correct identification of products A and B leads to: A = Na 2CrO4, B = CrO3