Question
Chemistry Question on Chemical Reactions of Haloalkanes and Haloarenes
A and B formed in the following reactions are: CrO2Cl2+4NaOH→A+2NaCl+2H2O A+2HCl+2H2O2→B+3H2O
\text{A} = \text{Na}_2\text{CrO}_4, \, \text{B} = \text{CrO}_3 \\\
\text{A} = \text{Na}_2\text{Cr}_2\text{O}_4, \, \text{B} = \text{CrO}_4 \\\
\text{A} = \text{Na}_2\text{Cr}_2\text{O}_7, \, \text{B} = \text{CrO}_3 \\\
\text{A} = \text{Na}_2\text{Cr}_2\text{O}_7, \, \text{B} = \text{CrO}_5 \\\
\text{A} = \text{Na}_2\text{CrO}_4, \, \text{B} = \text{CrO}_3 \\\
Solution
To analyze the reactions, we need to identify the products formed in each step.
First Reaction: The reaction of dichromate with sodium hydroxide produces sodium chromate:
Cr2O72− + 4NaOH -> 2Na2CrO4 + 2H2O
The product formed in this reaction is Na2CrO4.
Second Reaction: The sodium chromate reacts with chlorine gas and water. The products typically involve the formation of chromium trioxide:
A + 2Cl2 + 2H2O -> B + 3H2O
Here, B is identified as CrO3 (chromium trioxide) when considering oxidation reactions of chromium compounds.
Thus, the correct identification of products A and B leads to: A = Na 2CrO4, B = CrO3