Question
Question: \[\text{2C}\text{e}^{\text{4+}}\text{ + Co}\overset{\quad\quad}{\rightarrow}\text{2C}\text{e}^{\text...
$$$\text{= - 0.277 V hence,}{E^{0}}_{Ce^{4 +}/Ce^{3 +}}$is
A
0.805 V
B
1.62 V
C
– 0.805 V
D
– 1.61 V
Answer
1.62 V
Explanation
Solution
Eŗcell = 1.89 ; EŗCe4+/Ce3+ + EŗCo/Co2+ = E + 0.277 ⇒ E = 1.62 V