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Question: \(\text{ Xe}{{\text{F}}_{\text{6}}}\text{ }\) on hydrolysis gives: A) \(\text{ Xe}{{\text{O}}_{\te...

 XeF6 \text{ Xe}{{\text{F}}_{\text{6}}}\text{ } on hydrolysis gives:
A)  XeO3 \text{ Xe}{{\text{O}}_{\text{3}}}\text{ }
B)  XeO2 \text{ Xe}{{\text{O}}_{2}}\text{ }
C)  XeO \text{ XeO }
D)  Xe \text{ Xe }

Explanation

Solution

The xenon hexafluoride is a xenon compound. The  XeF6 \text{ Xe}{{\text{F}}_{\text{6}}}\text{ } undergoes the partial or complete hydrolysis reaction. Xenon hexafluoride on hydrolysis gives oxide as a product along with the hydrofluoric acid. The hydrolysis product is a strong oxidizing agent.

Complete Solution :
Xenon is a noble gas element. It is a fifth-period element. The electronic configuration of xenon is as shown below:
 Xe = [Kr]4d10 5s2 5p6 \text{ Xe = }\left[ \text{Kr} \right]4{{\text{d}}^{\text{10}}}\text{ 5}{{\text{s}}^{\text{2}}}\text{ 5}{{\text{p}}^{\text{6}}}\text{ }
- The valence shell of xenon contains 8 electrons. It also has an empty  5d \text{ 5d } orbital. The six fluorine atoms are bonded to the xenon atom through six covalent bonds and form a xenon hexafluoride compound. Xenon undergoes  sp3d3 \text{ s}{{\text{p}}^{\text{3}}}{{\text{d}}^{\text{3}}}\text{ } hybridization and has seven hybrid orbitals. Six hybrid orbitals form a covalent bond with six fluorine atoms and contain one lone pair of electrons.
The structure of xenon hexafluoride is as shown below:

 XeF6 \text{ Xe}{{\text{F}}_{\text{6}}}\text{ } is one of the three binary fluorides formed by xenon.
The xenon hexafluoride undergoes a complete hydrolysis reaction. The hydrolysis of  XeF6 \text{ Xe}{{\text{F}}_{\text{6}}}\text{ } forms a xenon trioxide  XeO3 \text{ Xe}{{\text{O}}_{\text{3}}}\text{ } and hydrofluoric acid  HF \text{ HF } .The reaction between the xenon hexafluoride and water is as shown below:
 XeF+ 3H2 XeO+ 6HF \text{ Xe}{{\text{F}}_{\text{6 }}}+\text{ 3}{{\text{H}}_{\text{2}}}\text{O }\to \text{ Xe}{{\text{O}}_{\text{3 }}}+\text{ 6HF }
The xenon trioxide is highly explosive in nature. It acts as a strong oxidizing agent in the solution.
So, the correct answer is “Option A”.

Note: Note that, the partial hydrolysis of  XeF6 \text{ Xe}{{\text{F}}_{\text{6}}}\text{ } gives oxyfluorides such as  XeOF4 \text{ XeO}{{\text{F}}_{\text{4}}}\text{ } and  XeO2F2 \text{ Xe}{{\text{O}}_{\text{2}}}{{\text{F}}_{2}}\text{ }. The reaction of partial hydrolysis of xenon hexafluoride is as follows:
\text{ }\left. \begin{aligned} & \text{Xe}{{\text{F}}_{\text{6}}}\text{ + }{{\text{H}}_{\text{2}}}\text{O }\to \text{ XeO}{{\text{F}}_{\text{4}}}\text{ }+\text{ 2HF } \\\ & \text{ Xe}{{\text{F}}_{\text{6}}}\text{ + 2}{{\text{H}}_{\text{2}}}\text{O }\to \text{ Xe}{{\text{O}}_{\text{2}}}{{\text{F}}_{2}}\text{ }+\text{ 4HF} \\\ \end{aligned} \right\\}\text{ Partial hydrolysis }