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Question

Physics Question on Current Electricity

 The Wheatstone bridge is an arrangement of four resistances, say R1,R2,R3, and R4. The null point condition is given by:\text{ The Wheatstone bridge is an arrangement of four resistances, say } R_1, R_2, R_3, \text{ and } R_4. \text{ The null point condition is given by:}

A

R1R2=R3R4\quad \frac{R_1}{R_2} = \frac{R_3}{R_4} \\\\

B

R1+R2=R3+R4\quad R_1 + R_2 = R_3 + R_4 \\\\

C

R1R2=R2R4\quad R_1 - R_2 = R_2 - R_4 \\\\

D

R1×R2=R3×R4\quad R_1 \times R_2 = R_3 \times R_4

Answer

R1R2=R3R4\quad \frac{R_1}{R_2} = \frac{R_3}{R_4} \\\\

Explanation

Solution

The Wheatstone bridge is balanced when the ratio of the two resistances in one branch equals the ratio of the two resistances in the other branch:
R1R2=R3R4\quad \frac{R_1}{R_2} = \frac{R_3}{R_4} \\\\This is the condition for zero current through the galvanometer.