Question

\text{The Spin only magnetic moment value of square planar complex } [\text{Pt(NH}_3\text{)}_2\text{Cl(NH}_2\text{CH}_3\text{)}]\text{Cl is } \\_\\_\\_\\_\\_\\_ \text{ B.M. (Nearest integer)} \\\ \text{(Given atomic number for Pt = 78)}

Answer 1

The complex $[ \text{Pt(NH}_3)_2 \text{Cl(NH}_2\text{CH}_3) ] \text{Cl}$ contains $\text{Pt}^{2+}$ in a square planar geometry.

$\text{Pt}^{2+}$ has a $d^8$ electronic configuration. In square planar complexes, the $d$-electrons pair up in such a way that no unpaired electrons remain. As a result, the magnetic moment is $0 \, \text{B.M.}$ (Bohr Magnetons).
The Correct answer is: 0