Question

$\text{Phenol} \xrightarrow{\text{(i) NaOH, (ii) CO}_2, \, \text{140°C}} \text{A} \xrightarrow{\text{H}^+/\text{H}_2\text{O}}\text{B}\xrightarrow{\text{Ac}_2\text{O}} \text{C}$
In the above reaction, end product 'C' is

• A. salicylaldehyde
• B. salicylic acid
• C. phenyl acetate
• D. aspirin

Answer 1

Answer: (D)

aspirin

Answer 2

The correct option is (D): aspirin