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Physics Question on Optics

 Light is incident on an interface between water (μ=43) and glass (μ=32).\text{ Light is incident on an interface between water } (\mu = \frac{4}{3}) \text{ and glass } (\mu = \frac{3}{2}).\\\\ For total internal reflection, light should be traveling from:\text{For total internal reflection, light should be traveling from:}

A

water to glass and ∠i>∠ic\quad \text{water to glass and } \angle i > \angle i_c \\\\

B

water to glass and ∠i<∠ic\quad \text{water to glass and } \angle i < \angle i_c \\\\

C

glass to water and ∠i<∠ic\quad \text{glass to water and } \angle i < \angle i_c \\\\

D

glass to water and ∠i>∠ic\quad \text{glass to water and } \angle i > \angle i_c

Answer

glass to water and ∠i>∠ic\quad \text{glass to water and } \angle i > \angle i_c

Explanation

Solution

Solution: Total internal reflection occurs when light travels from a denser medium to a rarer medium and the angle of incidence exceeds the critical angle. Here, glass (μ=32) is denser than water (μ=43). So, for total internal reflection, the light should be traveling from glass to water and the angle of incidence should be greater than the critical angle ∠ic.\textbf{Solution:} \text{ Total internal reflection occurs when light travels from a denser medium to a rarer medium and the angle of incidence exceeds the critical angle.}\\\ \text{Here, glass } (\mu = \frac{3}{2}) \text{ is denser than water } (\mu = \frac{4}{3}). \text{ So, for total internal reflection, the light should be traveling from glass to water}\\\ \text{and the angle of incidence should be greater than the critical angle } \angle i_c.