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Question: \({\text{BC}}{{\text{l}}_{\text{3}}}\) molecule is planar while \({\text{NC}}{{\text{l}}_{\text{3}}}...

BCl3{\text{BC}}{{\text{l}}_{\text{3}}} molecule is planar while NCl3{\text{NC}}{{\text{l}}_{\text{3}}} molecule is pyramidal because:
(A) BCl3{\text{BC}}{{\text{l}}_{\text{3}}} does not have lone pair on B but NCl3{\text{NC}}{{\text{l}}_{\text{3}}} has a lone pair of electron on N.
(B) B-Cl bond is more polar than N-Cl bond.
(C) N atoms are smaller than B atoms.
(D) N-Cl bond is more covalent than B-Cl bond.

Explanation

Solution

In the above question, we are asked why the structure of BCl3{\text{BC}}{{\text{l}}_{\text{3}}} and NCl3{\text{NC}}{{\text{l}}_{\text{3}}} is different. The reason for this is that the presence and absence of lone pairs decides the structure of the molecule.

Complete step by step solution
Since, we are asked about the structure difference between BCl3{\text{BC}}{{\text{l}}_{\text{3}}} and NCl3{\text{NC}}{{\text{l}}_{\text{3}}}. Let us first calculate the number of bond pairs and lone pairs present in the molecule.
For BCl3{\text{BC}}{{\text{l}}_{\text{3}}}:
Atomic number of B = 5
We know that the maximum number of electrons present in a particular shell is given by 2n2{\text{2}}{{\text{n}}^{\text{2}}}. Hence, in the first shell only two electrons are present, and the rest three in the second shell.
So, number of valence electrons = 3
Number of chlorine atom attached to it = 3
There is no lone pair. Hence, the shape is planar.
For NCl3{\text{NC}}{{\text{l}}_{\text{3}}}:
Atomic number of N = 7
So, in the first shell only two electrons and rive five electrons in the second shell.
Number of valence electrons = 5
Number of chlorine atom attached to it = 3
Two electrons are left which forms a lone pair. The lone pair bond pair repulsion is more than the bond pair bond pair repulsion. And hence, the structure of NCl3{\text{NC}}{{\text{l}}_{\text{3}}} is pyramidal.
So we can conclude that BCl3{\text{BC}}{{\text{l}}_{\text{3}}} molecule is planar whereas NCl3{\text{NC}}{{\text{l}}_{\text{3}}} molecule is pyramidal because BCl3{\text{BC}}{{\text{l}}_{\text{3}}} does not have lone pair on B but NCl3{\text{NC}}{{\text{l}}_{\text{3}}} has a lone pair of electron on N.
Therefore, the correct option is Option-A.

Note
In this type of question, first we have to find out the number of valence electrons present on the central atom. Then we can decide the structure keeping in mind if there is any lone pair or not.