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Question

Chemistry Question on Chemical Kinetics

A(g)B(g)\text{A(g)}\xrightarrow{{}}\text{B(g)} is a first order reaction. The initial concentration of A is 0.2molL1.\text{0}\text{.2}\,\text{mol}\,{{\text{L}}^{-1}}. After 10 min, the concentration of B is found to be 0.18molL1.\text{0}\text{.18}\,\text{mol}\,{{\text{L}}^{-1}}. The rate constant (inmin1)(in\,mi{{n}^{-1}}) for the reaction is

A

0.2303

B

2.303

C

0.693

D

0.01

Answer

0.2303

Explanation

Solution

Given, A(g)B(g)A(g)\xrightarrow{{}}B(g) (first order reaction) Initial concentration of A=0.2 mol L1A=0.2\text{ }mol\text{ }{{L}^{-1}} Concentration of B=0.18 molL1\text{B}=0.18\text{ mol}\,{{\text{L}}^{-1}} Concentration of A after 10 min =0.20.18=0.2-0.18 =0.02 mol L1=0.02\text{ mol }{{\text{L}}^{-1}} time (r)= 10 min Rate constant, k=2.303tlogaaxk=\frac{2.303}{t}\log \frac{a}{a-x} =2.30310log0.20.02=\frac{2.303}{10}\log \frac{0.2}{0.02} =0.2303min1=0.2303\,{{\min }^{-1}}