Question

\text{A constant current was passed through a solution of AuCl}_4^- \text{ ion between gold electrodes. After a} \\\\\text{period of 10.0 minutes, the increase in mass of cathode was 1.314 g. The total charge passed} \\\ \text{through the solution is \\_\\_\\_\\_\\_\\_\\_\\_} \times 10^{-2} \, \text{F.} \\\ $\text{(Given atomic mass of Au = 197)}$

Answer 1

Solution:

$\frac{W}{E} = \frac{\text{charge}}{1F}$

Substitute the values:
$\frac{1.314}{\frac{197}{3}} = \frac{Q}{1F}$

$Q = 2 \times 10^{-2} F$

The Correct Answer is: 2