Question
Question: \({\text{5 moles}}\) of an ideal gas at \({427^0}C\) expands isothermally and reversibly from a volu...
5 moles of an ideal gas at 4270C expands isothermally and reversibly from a volume of 6 L to 60 L. Calculate the work done in KJ.
Solution
One can use the formula of the work done for isothermal reversible expansion of gas. Analyze the given values in the question and convert the values whichever is necessary.
Complete step by step answer:
- First of all let's analyze the values given in the question and write them in their numerical denominations as follows,
Number of moles of an ideal gas (n) = 5 moles
Temperature (T)=4270C
The value of temperature is given in degree Celsius but we need this value in Kelvin,
4270C=427+273=700K
Therefore, Temperature (T)=700K
Initial volume (V1)=6L
Final volume (V2)=60L
Work done (W)= ?
Now as we analyzed all the values given in the question now let us see the formula for the calculation of work done for the isothermal reversible process as follows,
W=−nRTlnV1V2
Now, let's put the values in the above formula,
W=−5×8⋅314×700×(660)
As the value of R is common for an ideal gas.
Now let us calculate the values,
W=−29099×(10)
⇒W=−290990 J
As we need the value in kilojoules we need to convert this joules value. We can do so by dividing the joules value by one thousand to get the value in kilojoules as follows,
W=−290⋅990 KJ
Therefore, for a 5 moles of an ideal gas at 4270C which expands isothermally and reversibly from a volume of 6 L to 60 L the work done will be - 290⋅990 KJ.
Note:
The work done value is negative which means that the work is done in the opposite direction of the force applied. The concept of isothermal expansion means the gas undergoes expansion at a constant temperature which means there is no exchange of heat between the system and surrounding. The reversible reaction means there is a constant conversion of reactant to product and product to the reactant. This process goes on until some external force or reagent is applied.