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Question: Tertiary butyl alcohol gives tertiary butyl chloride on treatment with: (a) conc. \[HCl\] /anhydro...

Tertiary butyl alcohol gives tertiary butyl chloride on treatment with:
(a) conc. HClHCl /anhydrous ZnCl2ZnC{l_2}
(b) KCNKCN
(c) NaOClNaOCl
(d) Cl2C{l_2}

Explanation

Solution

First we have to know the various reagents that can be used to change alcohol into alkyl halides and then we go for further specification of the reagent which doesn't change the degree of the carbon and also the number of carbons before and after the reaction.

Complete answer:
So, the various reagents which change the alcohol into alkyl halides are:
(a) Using Zinc chloride ZnCl2ZnC{l_2} in presence of HClHCl :
ROH+HClZnCl2RCl+H2OR - OH + HCl\xrightarrow{{ZnC{l_2}}}R - Cl + {H_2}O (where, RR - is alkyl group)
For this reaction, conc. HClHCl requires anhydrous ZnCl2ZnC{l_2} as the catalyst.
(b) Using NaBrNaBr and H2SO4{H_2}S{O_4} :
ROH+NaBr+H2SO4RBr+NaHSO4R - OH + NaBr + {H_2}S{O_4} \to R - Br + NaHS{O_4} (where, RR - is alkyl group)
This process is used for preparation of alkyl bromide.
(c) Using PX3P{X_3} :
3ROH+PX33RX+H3PO33R - OH + P{X_3} \to 3R - X + {H_3}P{O_3} (where, RR - is alkyl group and X=Cl,BrX = Cl,Br )
(d) Using Red phosphorus in presence of X2{X_2}
ROHX2=Br2,I2redP/X2RXR - OH\xrightarrow[{{X_2} = B{r_2},{I_2}}]{{redP/{X_2}}}R - X (where, RR - is alkyl group and X=Br,IX = Br,I )
(e) Using PCl5PC{l_5} ,
ROH+PCl5RCl+POCl3+HClR - OH + PC{l_5} \to R - Cl + POC{l_3} + HCl (where, RR - is alkyl group)
(f) Using SOCl2SOC{l_2} ,
ROH+SOCl2RCl+SO2+HClR - OH + SOC{l_2} \to R - Cl + S{O_2} + HCl (where, RR - is alkyl group)
In all the above reagents SOCl2SOC{l_2} is most preferable for making alkyl chloride, because the by-products of this reaction are SO2S{O_2} and HClHCl which are released in the form of gases. Hence, easy to separable.
So, from the above all discussions,
We are trying to find out the correct option which converts tertiary butyl alcohol to tertiary butyl chloride.
In all the above options, only conc. HClHCl /anhydrous ZnCl2ZnC{l_2} can be used for converting tertiary butyl alcohol to tertiary butyl chloride.

Hence, the correct option is (a) conc. HClHCl /anhydrous ZnCl2ZnC{l_2}

Note:
Degree of the carbon is identified by the number of carbons attached with that carbon for which the degree of carbon is calculated. If the carbon is attached with one carbon, it is called Primary carbon, if with two, Secondary carbon and if with three tertiary carbon.