Ten one-rupee coins are put on top of each other on a table.... | Physics | SolveeIt | Solveeit

Today, August 18

Question

Ten one-rupee coins are put on top of each other on a table. Each coin has a mass $m$ . The force on the $7^{th}$ coin (counted from the bottom) due to all the coins on its top is

A

$3mg$ , vertically downwards

B

$3mg$ , vertically upwards

C

$7mg$ , vertically downwards

D

$7mg$ , vertically upwards

Answer

$3mg$ , vertically downwards

Explanation

Solution

The force on $7^{th}$ coin is due to weight of the three coins lying above it. $\therefore F = 3mg$ This force acts vertically downwards.