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Question

Physics Question on Current electricity

Ten identical wires each having a resistance of one ohm are connected in parallel. The combination will have a resistance of

A

0.1Ω0.1 \, \Omega

B

10Ω10 \,\Omega

C

0.01Ω0.01\, \Omega

D

1Ω1 \, \Omega

Answer

0.1Ω0.1 \, \Omega

Explanation

Solution

Given: No. of wires = 10 and resistance of each wire =1Ω= 1\,\Omega. We know that relation for equivalent resistance of wires connected in parallel 1Req=\frac{1}{R_{eq}}= 11+11+11++11\underbrace{\frac{1}{1}+\frac{1}{1}+\frac{1}{1}+\cdot\cdot\cdot\cdot\cdot+\frac{1}{1}} Req=110=0×1Ω.\therefore\,R_{eq} = \frac{1}{10}=0_{\times}1\,\Omega.