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Question: Temperature of an ideal gas is T K and average kinetic energy is \(E = 2.07 \times 10^{- 23}\)T Joul...

Temperature of an ideal gas is T K and average kinetic energy is E=2.07×1023E = 2.07 \times 10^{- 23}T Joule/molecule. Number of molecules in 1 litre gas at S.T.P. will be

A

2.68×10222.68 \times 10^{22}

B

2.68×10252.68 \times 10^{25}

C

2.68×10282.68 \times 10^{28}

D

1.68×10221.68 \times 10^{22}

Answer

2.68×10222.68 \times 10^{22}

Explanation

Solution

As we know that at S.T.P. 22.4 litre of gas contains 6.023×10236.023 \times 10^{23} molecules

∴ 1 litre of gas contain 6.023×102322.4=2.68×1022\frac{6.023 \times 10^{23}}{22.4} = 2.68 \times 10^{22} molecules.