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Question

Physics Question on kinetic theory

Temperature of an ideal gas, initially at 2727^{\circ}C, is raised by 66^{\circ}C. The rms velocity of the gas molecules will,

A

increase by nearly 2%

B

decrease by nearly 2%

C

increase by nearly 1%

D

decrease by nearly 1%

Answer

increase by nearly 1%

Explanation

Solution

Initial temperature of ideal gas,
T1=273+27=300KT_{1}=273+27=300\, K
when temperature of gas is raised by 6C6^{\circ} C, the final temperature of gas
T2=273+6+27T_{2} =273+6+27
=306K=306\, K
Let initial velocities are vrms1v_{ rms _{1}}, and vrms2v_{ rms _{2}}
vmsTv_{ ms } \propto \sqrt{T}
vrms1vmms2=T1T2\frac{v_{ rms _{1}}}{v_{ mms _{2}}} =\sqrt{\frac{T_{1}}{T_{2}}}
vrms2=T2T1×vrms1v_{ rms _{2}} =\sqrt{\frac{T_{2}}{T_{1}}} \times v_{ rm s_{1}}
=306300×vrms1=\sqrt{\frac{306}{300}} \times v_{ rms _{1}}
=100×vms1=1 \cdot 00 \times v_{ ms _{1}}
So, it will increase by 1%1 \%