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Question: Temp Vs pressure graph of an ideal gas is shown. Then during the process AB. ![](https://cdn.purees...

Temp Vs pressure graph of an ideal gas is shown. Then during the process AB.

A

Internal energy of the gas continuously decreases

B

Volume of the gas increases

C

Work done by atmosphere on the gas is + Ve

D

Temperature is directly proportional to pressure

Answer

Work done by atmosphere on the gas is + Ve

Explanation

Solution

Volume decreases, so work done by gas is negative two equal parts A and B. Part A has an ideal gas at pressure P0 and temperature T0 and in part B is vacuum. A massless spring of force constant k is connected with piston and the wall of the container as shown. Initially spring is unstretched. Gas in chamber A is allowed to expand. Let in equilibrium spring is compressed by x0. Then –

(1) final pressure of the gas is

(2) work done by the gas is 12kx02\frac { 1 } { 2 } \mathrm { kx } _ { 0 } ^ { 2 }

(3) change in internal energy of the gas is 12kx02\frac { 1 } { 2 } \mathrm { kx } _ { 0 } ^ { 2 }

(4) temperature of the gas is decreased