Te roots of (a + c – b) x2 + 2cx + (b + c – a) = 0, a ¹ b, a... | MATH - SOLUTION OF QUADRATIC EQUATIONS AND NATURE OF ROOTS | SolveeIt | Solveeit

Today, October 3

Question

Te roots of (a + c – b) x² + 2cx + (b + c – a) = 0, a ¹ b, are

A

Real and unequal

B

Imaginary

C

Real and equal

D

None of these

Answer

Real and unequal

Explanation

Solution

D = 4[c² – (a + c – b) (b + c – a)]

= 4 [c²– (c² – (a – b)²)]

= 4 (a – b)²] But a ¹ b

Ž D > 0 roots are real and unequal.