Question

The molar heat capacity for a process is :

C = $\frac { \mathrm { R } } { \gamma - 1 }$+ , then process equation is –

• A. Ve^–(a/R)T = constant
• B. Ve^(a/R)T = constant
• C. VT = constant
• D. Ve^a/RT = constant

Answer 1

Answer: (D)

Ve^a/RT = constant

Answer 2

$\mathrm { C } = \mathrm { C } _ { \mathrm { V } } + \frac { \mathrm { PdV } } { \mathrm { dT } }$

=

=

lnV = –+ ln C

$\frac { \mathrm { V } } { \mathrm { C } }$ = e^–a/RT

Ve^a/RT = C