test","extracted_subject":"MATH","extracted_chapter":"PERMUTATIONS AND COMBINATIONS","extracted_topic":"DEFINITION OF PERMUTATION, NUMBER OF PERMUTATIONS WITH OR WITHOUT REPETITION","questionPreviewUrl":"https://cdn.pureessence.tech/question-previews/packed_canvases/canvas_2008.png?top_left_x=1064&top_left_y=0&width=532&height=241&app=solveeit"},"seo_metadata":{"keywords":[]},"doubt_solver_data":{"concept_summary":[]},"embeddings":[],"is_hidden":false,"_id":"66d23e72425d76b7ab31f5b9","slug":"td-tdtd-tdtd-tdtd-tdtd-tdtd-tdtd-tdtd-tr-tbody-tab","content":"\n\n\n\n\n\n\n\n\n\n\n\nThe number of 7 digit numbers which can be formed using the digits 1, 2, 3, 2, 3, 3, 4 is.","options":[{"_id":"68aad1d17f15af4716dd9bf5","text":"420","sequence":0,"isCorrect":true},{"_id":"68aad1d17f15af4716dd9bf6","text":"840","sequence":1,"isCorrect":false},{"_id":"68aad1d17f15af4716dd9bf7","text":"2520","sequence":2,"isCorrect":false},{"_id":"68aad1d17f15af4716dd9bf8","text":"5040","sequence":3,"isCorrect":false}],"correct_answer":"420","explanation":"Required number = \\(\\frac{7\\mspace{6mu}!}{3\\mspace{6mu}!\\mspace{6mu} 2\\mspace{6mu}!} = \\frac{5040}{6 \\times 2} = 420\\).\n\n(\\(\\because\\)3 is repeated thrice and 2 is repeated twice).","question_type":"single_choice","appeared_in":[],"created_at":"2024-08-30T21:49:38.701Z","__v":0,"vector_store_id":"e5387931-83a6-4df2-93e0-22121482d6a1","updated_at":"2024-08-30T21:49:38.701Z","isStarred":false},"params":{"questionSlug":"td-tdtd-tdtd-tdtd-tdtd-tdtd-tdtd-tdtd-tr-tbody-tab"}}]}]]

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