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Question: \[\tan\theta\sin\left( \frac{\pi}{2} + \theta \right)\cos\left( \frac{\pi}{2} - \theta \right) =\]...

tan⁡θsin⁡(π2+θ)cos⁡(π2−θ)=\tan\theta\sin\left( \frac{\pi}{2} + \theta \right)\cos\left( \frac{\pi}{2} - \theta \right) =

A

1

B

0

C

12\frac{1}{\sqrt{2}}

D

None of these

Answer

None of these

Explanation

Solution

tan⁡θcos⁡θsin⁡θ=sin⁡2θ\tan\theta\cos\theta\sin\theta = \sin^{2}\theta.