Question
Question: Tangents OP and OQ are drawn from the origin O to the circle x<sup>2</sup> + y<sup>2</sup> + 2gx + 2...
Tangents OP and OQ are drawn from the origin O to the circle x2 + y2 + 2gx + 2fy + c = 0. Then the equation of the circumcircle of the triangle OPQ is –
A
x2 + y2 + 2gx + 2fy = 0
B
x2 + y2 + gx + fy = 0
C
x2 + y2 – gx – fy = 0
D
x2 + y2 – 2gx – 2fy = 0
Answer
x2 + y2 + gx + fy = 0
Explanation
Solution
OC diameter
(x – 0)(x + g) + (y – 0)(y + f) = 0
x2 + y2 + gx + fy = 0