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Question: Tangent is drawn to ellipse \(\frac{x^{2}}{27} + y^{2} = 1\)are \(( 3 \sqrt { 3 } \cos \theta , \sin...

Tangent is drawn to ellipse x227+y2=1\frac{x^{2}}{27} + y^{2} = 1are (33cosθ,sinθ)( 3 \sqrt { 3 } \cos \theta , \sin \theta ) [whereθε(0,π2)]\left\lbrack where\theta\varepsilon\left( 0,\frac{\pi}{2} \right) \right\rbrack. Then the value of θ such that sum of intercepts on axes made by this tangent is minimum is

A

π/3

B

π/4

C

π/6

D

π/8

Answer

π/6

Explanation

Solution

xcosθ33+ysinθ=1\frac{x\cos\theta}{3\sqrt{3}} + y\sin\theta = 1

Sum of intercepts = 33\sqrt{3}secθ + cosec θ = f(θ) (say).

⇒ f' (θ) = 33sin3θcos3θsin2θcos2θ\frac{3\sqrt{3}\sin^{3}\theta - \cos^{3}\theta}{\sin^{2}\theta\cos^{2}\theta}

⇒ at θ = π/6, f(θ) is minimum.