Solveeit Logo

Question

Question: \[\tan x - x + c\]...

tanxx+c\tan x - x + c

A

x+tanx+cx + \tan x + c

B

xtanx+cx - \tan x + c

C

xcotx+c- x - \cot x + c

D

ax3+bx2+cx4dx\int_{}^{}{\frac{ax^{3} + bx^{2} + c}{x^{4}}dx}

Answer

xcotx+c- x - \cot x + c

Explanation

Solution

23(1tan2x)2/3+c- \frac{2}{3}(1 - \tan^{2}x)^{2/3} + c

sin2xsin5xsin3x6mudx=\int_{}^{}\frac{\sin 2x}{\sin 5x\sin 3x}\mspace{6mu} dx =