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Question

Mathematics Question on Inverse Trigonometric Functions

tan(2tan115+sec152+2tan118)\tan \left(2 \tan ^{-1} \frac{1}{5}+\sec ^{-1} \frac{\sqrt{5}}{2}+2 \tan ^{-1} \frac{1}{8}\right) is equal to:

A

1

B

2

C

14\frac{1}{4}

D

54\frac{5}{4}

Answer

2

Explanation

Solution

The correct option is (B): 2