\[{\tan h}^{- 1}x =] | MATH - HYPERBOLIC FUNCTIONS | SolveeIt

${\tan h}^{- 1}x =$

$\frac{1}{2}\log\left( \frac{x + 1}{x - 1} \right)$

$\frac{1}{2}\log\left( \frac{x - 1}{x + 1} \right)$

$\frac{1}{2}\log\left( \frac{1 - x}{1 + x} \right)$

$\frac{1}{2}\log\left( \frac{1 + x}{1 - x} \right)$

Answer

$\frac{1}{2}\log\left( \frac{1 + x}{1 - x} \right)$

Explanation

It is obvious.

Question: \[{\tan h}^{- 1}x =\]...