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Question: \(\tan A + \cot(180^{o} + A) + \cot(90^{o} + A) + \cot(360^{o} - A)\) equal To...

tan⁡A+cot⁡(180o+A)+cot⁡(90o+A)+cot⁡(360o−A)\tan A + \cot(180^{o} + A) + \cot(90^{o} + A) + \cot(360^{o} - A) equal

To

A

0

B

2tan⁡A2\tan A

C

2cot⁡A2\cot A

D

2(tan⁡A−cot⁡A)2(\tan A - \cot A)

Answer

0

Explanation

Solution

tan⁡A+cot⁡A+(−tan⁡A)+(−cot⁡A)=0\tan A + \cot A + ( - \tan A) + ( - \cot A) = 0.