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Question

Mathematics Question on Inverse Trigonometric Functions

tan(2tan1(25))tan(2tan^{-1}(\frac{2}5)) is equal to

A

85\frac8{5}

B

1021\frac{10}{21}

C

2021\frac{20}{21}

D

2125\frac{21}{25}

E

425\frac{4}{25}

Answer

2021\frac{20}{21}

Explanation

Solution

The correct option is (C): 2021\frac{20}{21}