Question
Mathematics Question on Inverse Trigonometric Functions
tan(2sin−1(135))=
A
7851
B
3960
C
119160
D
119120
Answer
119120
Explanation
Solution
2sin−1135=sin−1169120=tan−1119120
tan(2sin−1(135))=
7851
3960
119160
119120
119120
2sin−1135=sin−1169120=tan−1119120