(tan^{-1}(\frac {1+\sqrt 3}{3+\sqrt 3})+sec^{-1}(\sqrt {\fra... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

$tan^{-1}(\frac {1+\sqrt 3}{3+\sqrt 3})+sec^{-1}(\sqrt {\frac {8+4\sqrt 3}{3+3\sqrt 3})}$ is equal to:

A

$\frac \pi6$

B

$\frac \pi3$

C

$\frac \pi4$

D

$\frac \pi2$

Answer

$\frac \pi3$

Explanation

Solution

The correct option is (B): $\frac \pi3$