Question
Mathematics Question on Limits
Tx→0+lim (xnlnx),n>0
A
does not exist
B
exists and is zero
C
exists and is 1
D
exists and is e−1
Answer
exists and is zero
Explanation
Solution
x→0+lim xn1ℓnx(∞∞). Applying LH rule
⇒x→0+limxn+1−nx1=0
Tx→0+lim (xnlnx),n>0
does not exist
exists and is zero
exists and is 1
exists and is e−1
exists and is zero
x→0+lim xn1ℓnx(∞∞). Applying LH rule
⇒x→0+limxn+1−nx1=0