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Question

Question: System is shown in the figure. Assume that cylinder remains in contact with the two wedges. The velo...

System is shown in the figure. Assume that cylinder remains in contact with the two wedges. The velocity of cylinder is –

A

1943u2 m/s\sqrt { 19 - 4 \sqrt { 3 } } \frac { \mathrm { u } } { 2 } \mathrm {~m} / \mathrm { s }

B

13u2 m/s\frac { \sqrt { 13 } \mathrm { u } } { 2 } \mathrm {~m} / \mathrm { s }

C

3um/s\sqrt { 3 } \mathrm { um } / \mathrm { s }

D

7um/s\sqrt { 7 } \mathrm { um } / \mathrm { s }

Answer

7um/s\sqrt { 7 } \mathrm { um } / \mathrm { s }

Explanation

Solution

In the frame of A

3u sin 300 = VY cos 300

̃ VY = 3u tan 300 = 3\sqrt { 3 } u

and VX = 2u ̃ V = VX2+VY2\sqrt { V _ { X } ^ { 2 } + V _ { Y } ^ { 2 } } = 7\sqrt { 7 } u