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Question

Physics Question on Surface tension

Surface tension of liquid is 5 N/m5\,N/m. If a thin film of area 0.02 m20.02 \,m^2 is made in a ring then the surface energy will be :

A

5×10−3 J5 \times 10^{-3}\, J

B

2.5×10−3 J2.5 \times 10^{-3}\, J

C

1×10−1 J1 \times 10^{-1}\, J

D

5×10−1 J5 \times 10^{-1}\, J

Answer

1×10−1 J1 \times 10^{-1}\, J

Explanation

Solution

Surface energy =T.A=T . A =5×0.02=0.1=5 \times 0.02=0.1 =1×10−1 J=1 \times 10^{-1} \,J