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Question

Physics Question on pascals law

Surface mass density of a disc is given by σ=kr2\sigma = kr^2 (where r is distance from centre) find moment of inertia about axis passing through the centre and perpendicular to plane -

A

kπr63\frac{k \pi r^6}{3}

B

kπr66\frac{k \pi r^6}{6}

C

2kπr65\frac{ 2 k \pi r^6}{5}

D

3kπr65\frac{ 3 k \pi r^6}{5}

Answer

kπr63\frac{k \pi r^6}{3}

Explanation

Solution

Answer (a) kπr63\frac{k \pi r^6}{3}