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Question

Question: Suppose we employ a system in which the unit of mass equals 100 kg, the unit of length equals 1 km a...

Suppose we employ a system in which the unit of mass equals 100 kg, the unit of length equals 1 km and the unit of time 100 s and call the unit of energy eluoj (joule written in reverse order), then

A

1 eluoj = 104 joule

B

1 eluoj = 10-3 joule

C

1 eluoj = 10-4 joule

D

1 joule = 103 eluoj

Answer

1 eluoj = 104 joule

Explanation

Solution

[E]=[ML2T2]\lbrack E\rbrack = \lbrack ML^{2}T^{- 2}\rbrack

1 eluoj =[100 kg]×[1 km]2×[100sec]2= [ 100 \mathrm {~kg} ] \times [ 1 \mathrm {~km} ] ^ { 2 } \times [ 100 \mathrm { sec } ] ^ { - 2 }

=100kg×106m2×104sec2=104kgm2×sec2= 100kg \times 10^{6}m^{2} \times 10^{- 4}\sec^{- 2}{} = 10^{4}kgm^{2} \times \sec^{- 2}{}

=104Joule= 10^{4}Joule