Question
Question: Suppose the resistors \({R_1}\), \({R_2}\) and \({R_3}\) have the values \(5\Omega \),\(10\Omega \) ...
Suppose the resistors R1, R2 and R3 have the values 5Ω,10Ω and 30Ω respectively. Which have been connected to a battery of 12V in a parallel connection. Calculate
1. Current through each resistor
2. Total current in the circuit
3. Total circuit resistance
Solution
Current through each resistor can be calculated applying Ohm’s law as we are provided with voltage of the circuit and the individual resistances of each resistor.Total current can be calculated using the Ohm’s law as the voltage of the circuit is already given.Resistances are given in the parallel connection.
Complete Step by Step Answer:
GIVEN THAT R1=5Ω R2=10Ω R3=30Ω V=12Volt
1. Firstly, calculating current through each resistor:
For R1=5Ω
Using ohm’s law I1=R1V
I1=512=2.4A
Like ways we can calculate current through each resistor.
For R2=10Ω
I2=R2V=1012
⇒I2=1.2A
For R3=30Ω
⇒I3=R3V ⇒I3=3012
∴I3=0.4A
2. Total current in the circuit(I):
Firstly, do part (3)solved below
Using Ohm’s law
V=IR
⇒I=312 ∴I=4A
TOTAL CURRENT IS 4A.
3. Total circuit resistance (R): As we all know from the question the resistances are connected in parallel, applying the resistances formula
R1=R11+R21+R31
⇒R1=51+101+301
⇒R1=306+3+1=3010
∴R=3Ω
TOTAL RESISTANCE IS 3Ω.
Note: Resistors are said to be connected in parallel when both of their terminals are respectively connected to each terminal of the other resistor or resistors. The current in each branch of a parallel connection circuit is different. Resistors in a parallel have common voltage across them.