Question
Mathematics Question on Straight lines
Suppose the point P(1,1) is translated to Q in the direction of y = 2x. If PQ=1,then Qis
A
(2,0)
B
(0,2)
C
(√2√2+1,√2√2+1)
D
(√5√5+1,√5√5+2)
E
(22+√3,23)
Answer
(√5√5+1,√5√5+2)
Explanation
Solution
Given that:
y=2x, is the equation of the line passing through the points P(1,1)
So , y−1=2(x−1)
⇒y=2x−1
Let the position of Q be (x1,y1)
Since, Q(x1,y1) lies on this line
⇒y1=2x1−1 ----------(1)
Also, given P is translated to Q by a unit distance (As PQ=1)
PQ=1
⇒(x1−1)2+(y1−1)2=1
⇒(x1−1)2+(2x1−2)2=1 (from equation (1))
⇒5x12−10x1+4=0
Now to get values of x1 from the quadratic equation we can write:
⇒x1=1010±√20
⇒x1=55±√5
⇒x1=1±√51
Substitute the above value in equation(1), we get
⇒y1=1±√52
Hence, the new position of P is (1±√51,1±√52)(Ans)