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Question

Mathematics Question on Quadratic Equations

Suppose that two persons AA and BB solve the equation x2+ax+b=0{{x}^{2}}+ax+b=0 . While solving AA commits a mistake in the coefficient of xx was taken as 1515 in place of 9-9 and finds the roots as 7-7 and 2-2 . Then, the equation is

A

x2+9x+14=0{{x}^{2}}+9x+14=0

B

x29x+14=0{{x}^{2}}-9x+14=0

C

x2+9x14=0{{x}^{2}}+9x-14=0

D

x29x14=0{{x}^{2}}-9x-14=0

Answer

x29x+14=0{{x}^{2}}-9x+14=0

Explanation

Solution

Let the incorrect equation is x2+15x+b=0{{x}^{2}}+15x+b=0 .
Since, roots are 7-7 and 2-2 .
\therefore Product of roots, b=14b=14
So, correct equation is x29x+14=0{{x}^{2}}-9x+14=0