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Question

Mathematics Question on Time and Work

Suppose that a maximum of 25 g of salt dissolves in 100 g of water. Any more salt, if added, remains undissolved and a sediment falls at the bottom. Now, water is evaporated from 1 kg of a 4% solution at the rate of 28 g per hour. After how long will it start sedimenting, approximately?

A

29 h

B

31 h

C

35 h

D

23 h

Answer

31 h

Explanation

Solution

25 gm salt in 100 gm water

1 gm =10025=\frac{100}{25}

40 gm =10025×40=160=\frac{100}{25}\times40=160 gm

Water is evaporated at 28 gms per hour
From option C, we get
after 30 hrs
water loss = 30×\times28
= 840
Present value of water = 1000 - 840 = 160 gms
After 30 hrs, water will start to reduce and salt will begin to sediment.
So the correct option is (B)